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Ensiferous3  





Joined: 02 Jul 2006
Posts: 1629

PostPosted: Sun Oct 08, 2006 11:47 pm    Post subject: RIDDLES! Reply with quote

Come on, we need a riddle topic! How's about it guys? I'll start it off:

The Paths and Brothers

You are walking along a path you have never travelled before, cause you are cool like that. You come to a fork in the road. One path leads to certain doom and despair and other bad D words. The other, leads to Peace, Prosperity and other good P words Mr. Green . Also at the fork is a shack. In the shack live two brothers, the brother of Truth and the brother of Lies. The Brother of Truth always tells the truth (duh) and the Brother of Lies always... you guessed it, lies! You can ask them a single question. What do you ask one of them (obviously a question pertaining to getting on the good path!)

Solved by: Matt


And for a SUPER hard one (I couldn't figure it out ):

The Three Gods of Time

You enter a chamber of three all-knowing gods. The gods speak the truth always but are bound by these things: The God of the Past, answers the question that was previously asked, such as when you ask question 3, he answers question 2. The only exception is during the first question where he answers the same as either the God of Present or Future. The God of the Present answers every question at the correct time, such as answering Q2 during Q2. The God of the Future answers the question that will be asked in the future (the next question). So when you ask Q1, he answers Q2 (even though you may not even know it yet, spoooooooky ). On question 3 he will agree with either of the other gods. Also, the gods know not any language of man and answer questions using Da or Na meaning yes or no. However, you know not which means which, and you need to determine it. The Gods all answer at relatively the same time, you do not ask each of them individually.

You can ask them three Yes or No questions to determine the identity of each God.

Solved by: HylianHero

Post your riddles!

EDIT: I ommitted a single detail from the Gods one. Fixed.
EDIT 2: Make it a little clearer for the Gods one.
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Last edited by Ensiferous3 on Mon Oct 09, 2006 2:42 pm; edited 2 times in total
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Matt  





Joined: 04 Feb 2006
Posts: 3780
Location: Bethel, Vermont

PostPosted: Mon Oct 09, 2006 12:04 am    Post subject: Reply with quote

Riddle 1: obviously, 1 always answers negative and onepositive, and a negative and a positive makes a negative. Therefore, if you include both of their answers, you will know you always have a negative, or a lie. Ask either one what the other one would say the road to doom and despair leads to, and take that one.

You could also ask "If I were to ask you which road led to peace and prosperity, what would you answer". and take whatever they say, since you'd get either a double negative or a double positive, both resulting in a positive.
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Ensiferous3  





Joined: 02 Jul 2006
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PostPosted: Mon Oct 09, 2006 12:09 am    Post subject: Reply with quote

Damn, nice one Matt (though it wasn't too hard)! Now figure out the God one !
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Matt  





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PostPosted: Mon Oct 09, 2006 12:11 am    Post subject: Reply with quote

I had heard the first answer before, but it dawned on me the second one worked as well. It's all logic
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Ensiferous3  





Joined: 02 Jul 2006
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PostPosted: Mon Oct 09, 2006 12:13 am    Post subject: Reply with quote

As is the God one. Literally Mr. Green , all logic.
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Jackhammer  





Joined: 04 Oct 2006
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PostPosted: Mon Oct 09, 2006 12:41 am    Post subject: Reply with quote

If the answer to my next question was NO, what would the god of past say?
If the answer to my first question was YES, what would the god of the future say?
Are you the god of present?


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Ensiferous3  





Joined: 02 Jul 2006
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PostPosted: Mon Oct 09, 2006 12:51 am    Post subject: Reply with quote

I don't understand to be honest (at least not that answer). Could you explain it step by step, as in which god answers how and how you know which god is which?

Cause the way I know is way different .
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Jackhammer  





Joined: 04 Oct 2006
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PostPosted: Mon Oct 09, 2006 12:55 am    Post subject: Reply with quote

i have no clue honestly i just thought it might be right


in the mean time try this one


In complex analysis, an entire function is defined as a function which is
infinitely differentiable at every point in C (for example: constants,
polynomials, e^x, etc.). Picard's Theorem says that every nonconstant
entire function f misses at most one point (i.e. f(C) = C or C-{x0}).
For example, every nonconstant polynomial hits every point, and e^x misses
only 0.

Now consider the function f(x) = e^(e^x). Since e^x is entire, f is also
entire by the chain rule. But it misses 0 since the base e^y misses 0,
and it misses 1 since the top e^x misses 0 so that e^(e^x) misses e^0 = 1.
But by Picard's Theorem there can be only one missing point, so the two
missing points must be the same. Therefore, 0 = 1.

Where's the flaw in the argument?

Keep this in mind

ez = eRe(z)*ei*Im(z)
= eRe(z)*(cos(Im(z))+i*sin(Im(z)))
Therefore, ez indeed hits all complex number besides 0.


Last edited by Jackhammer on Mon Oct 09, 2006 1:04 am; edited 1 time in total
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Ensiferous3  





Joined: 02 Jul 2006
Posts: 1629

PostPosted: Mon Oct 09, 2006 1:02 am    Post subject: Reply with quote

Thats hardly a riddle, its a math problem ! Oh god dammit I know this one though... I just can't remember what the answer is Mr. Green !

It was a random fact my 8th grade math teacher tought me and I can't even think of it now.

EDIT: Thanks for crushing every last bit of hope I had for solving this problem by throwing in that equation at the bottom ! I have no idea, where are you mathletes when you need em?
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schzoidbaka  





Joined: 10 Jul 2006
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Location: The Town of Awesome

PostPosted: Mon Oct 09, 2006 5:46 am    Post subject: Reply with quote

Jackhammer wrote:
i have no clue honestly i just thought it might be right


in the mean time try this one


In complex analysis, an entire function is defined as a function which is
infinitely differentiable at every point in C (for example: constants,
polynomials, e^x, etc.). Picard's Theorem says that every nonconstant
entire function f misses at most one point (i.e. f(C) = C or C-{x0}).
For example, every nonconstant polynomial hits every point, and e^x misses
only 0.

Now consider the function f(x) = e^(e^x). Since e^x is entire, f is also
entire by the chain rule. But it misses 0 since the base e^y misses 0,
and it misses 1 since the top e^x misses 0 so that e^(e^x) misses e^0 = 1.
But by Picard's Theorem there can be only one missing point, so the two
missing points must be the same. Therefore, 0 = 1.

Where's the flaw in the argument?

Keep this in mind

ez = eRe(z)*ei*Im(z)
= eRe(z)*(cos(Im(z))+i*sin(Im(z)))
Therefore, ez indeed hits all complex number besides 0.


is e just a variable or is it that natural number that occurs or something like that?

and where the hell did e^y come from if we're only talking about one entire, e^x?

this all could be crap I haven't learned yet in some advanced math, for I am only in Pre-Calculus Honors...
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HylianHero  





Joined: 22 Feb 2006
Posts: 4673
Location: Santa Cruz, CA

PostPosted: Mon Oct 09, 2006 6:09 am    Post subject: Reply with quote

Holy crap...that last one's a doozy...I'll give it a shot, but it's probably completely wrong.

All right, here we go.

"Are you a god?"
"Are you not a god?"
"Are you a god?"

For the first question, the Gods of Past and Present will say yes. The God of Future will say no, since he answers the next question. The next question will let the Gods of Past and Future say yes, but the God of Present say no. The next question will let the Gods of Future and Present answer yes, and the God of Past will answer no.

Mr. Green Mr. Green Mr. Green That makes sense right?
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Matt  





Joined: 04 Feb 2006
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Location: Bethel, Vermont

PostPosted: Mon Oct 09, 2006 7:38 am    Post subject: Reply with quote

Jackhammer wrote:
i have no clue honestly i just thought it might be right


in the mean time try this one


In complex analysis, an entire function is defined as a function which is
infinitely differentiable at every point in C (for example: constants,
polynomials, e^x, etc.). Picard's Theorem says that every nonconstant
entire function f misses at most one point (i.e. f(C) = C or C-{x0}).
For example, every nonconstant polynomial hits every point, and e^x misses
only 0.

Now consider the function f(x) = e^(e^x). Since e^x is entire, f is also
entire by the chain rule. But it misses 0 since the base e^y misses 0,
and it misses 1 since the top e^x misses 0 so that e^(e^x) misses e^0 = 1.
But by Picard's Theorem there can be only one missing point, so the two
missing points must be the same. Therefore, 0 = 1.

Where's the flaw in the argument?

Keep this in mind

ez = eRe(z)*ei*Im(z)
= eRe(z)*(cos(Im(z))+i*sin(Im(z)))
Therefore, ez indeed hits all complex number besides 0.


It would seem that your flaw is stating that e^x is entire :p
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Ensiferous3  





Joined: 02 Jul 2006
Posts: 1629

PostPosted: Mon Oct 09, 2006 11:44 am    Post subject: Reply with quote

HylianHero wrote:
Holy crap...that last one's a doozy...I'll give it a shot, but it's probably completely wrong.

All right, here we go.

"Are you a god?"
"Are you not a god?"
"Are you a god?"

For the first question, the Gods of Past and Present will say yes. The God of Future will say no, since he answers the next question. The next question will let the Gods of Past and Future say yes, but the God of Present say no. The next question will let the Gods of Future and Present answer yes, and the God of Past will answer no.

Mr. Green Mr. Green Mr. Green That makes sense right?


Well what if Past agrees with Future in question one? Remember Past and Future only answer 2 questions and agree with another God on the ones they can't (Past can't answer Question 0 and Future can't answer Question 4 because they aren't there). It may work and if it does step by step please like this :


WARNING, ANSWER TO THE GOD RIDDLE HERE, IF YOU WANT TO SOLVE IT DO NOT READ ON! Scroll to the END SPOILERS SIGN

Question 1: Does 2 + 2 = 5?
God 1: Da
God 2: Na
Gods 3: Na

Right here you seperate Future and Present, you don't know which is which but one is left out. The Past god matters not what he says here. So right now, either the God of the Present or Future said Da, we don't know just yet. As you know, the God of the present is answering 2 + 2 = 5 but the god of the future is answer 2 + 2 = 4.

Question 2: Does 2 + 2 = 4

God 1: Na
God 2: Da
God 3: Na

Both Gods of Future and Present gods answer yes because the next question is similar to 2 + 2 = 4. The past god however, answers NO because 2 + 2 does not = 5. Therefore Da is no (because the other two gods HAD to say yes).

Question 3: Does 3 + 3 =6

God 1: Na
God 2: Na
God 3: Na

This question is unimportant as long as it is true. The only use for this question is to get the Future god to answer yes to the previous question.

In question 1, you determine which two could be Present and Future. In question two you determine whether or not Da is yes or Na is yes, which then returns to question one. Therefore, the one(s) who answered No in the first one, would have to be either Present or Past. Well question two (and three) also determines who is past by him being the only one answering no. The future god is determined by process of elminiation because the Past God has to be #2 and the Present God has to be #1 so the Future God is number 3.

Here is a simplier way:

Is 2 + 2 = 5?

God 1: No
God 2: (Doesn't matter but I'll use Yes)
God 3: Yes

Is 2 + 2 = 4

God 1: Yes
God 2: No
God 3: Yes

Is 3 + 3 = 6

God 1: Yes
God 2: Yes
God 3: (Again, doesn't matter because both said yes, remember this question was only to determine what Da and Na meant in question 2).

God 1: Present
God 2: Past
God 3: Future


END SPOILERS
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HylianHero  





Joined: 22 Feb 2006
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PostPosted: Mon Oct 09, 2006 1:54 pm    Post subject: Reply with quote

GOD RIDDLE SPOILERS. DON'T READ THIS POST IF YOU WANT TO ANSWER.

Didn't I do that with my questions though? The first one seperates Future immediately, since it has to answer No while the other two (since Past HAS to answer Yes, since it agrees with Present) say Yes. The second question has Past and Future answering Yes, based off of the first and third questions, and has Present being the only one that answers No. The third question itself is completely unnecessary, since like you said, it only has to be true to work. All of the gods will answer Yes, except for Past. By distinguishing the order in which they answered no, you have the Gods.

But how is your answer different from mine, beyond just using number equations instead of just asking? Doesn't it result in the same thing?

Quote:

Well what if Past agrees with Future in question one? Remember Past and Future only answer 2 questions and agree with another God on the ones they can't (Past can't answer Question 0 and Future can't answer Question 4 because they aren't there). It may work and if it does step by step please like this :


Past will never agree with Future. As you said in the question, if Past is answering the first question, he will agree with Present. If Future is answering the last question, he will agree with Present. Here's what it'll look like.

Past: Q1, Q1, Q2 (NEVER answers Q3)
Present: Q1, Q2, Q3
Future: Q2, Q3, Q3 (NEVER answers Q1)

As you can see, Past repeats his answer twice for 1, and Future repeats his answer for 3.

%
%%%
%
%%%
%
%%%
%
%%%
%
%%%
%
%%%

/SPOILERS
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Ensiferous3  





Joined: 02 Jul 2006
Posts: 1629

PostPosted: Mon Oct 09, 2006 2:05 pm    Post subject: Reply with quote

I'm just missing one thing, if you reread the question I said this:

"The only exception is during the first question where he answers the same as either the God of Present or Future"
And the same is true for the God of the Future. They don't specically agree with Present, could be Present or Future/Past.

Unless that is taken into account, but I don't see it. Can you explain a little further?
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